#110. [LeetCode / MySQL] 1907. Count Salary Categories

문제 입력 코드 (SELECT "Low Salary" AS category, (SELECT COUNT(account_id) FROM Accounts WHERE income = 20000 and income 50000) AS accounts_count) 코드 설명 #SELECT #COUNT #UNION #UNION ALL 문제 출처 LeetCode - The World's Leading Online Programming Learning Platform Level up your ..

• format_list_bulleted SQL
• · 2023. 10. 6.
• textsms

#105. [LeetCode / MySQL] 1789. Primary Department for Each Employee

문제 입력 코드 1. SELECT employee_id, department_id FROM Employee GROUP BY employee_id HAVING COUNT(employee_id) = 1 UNION SELECT employee_id, department_id FROM Employee WHERE primary_flag = 'Y' 2. SELECT DISTINCT employee_id, department_id FROM Employee WHERE employee_id IN ( SELECT employee_id FROM Employee GROUP BY employee_id HAVING COUNT(*) = 1 ) OR primary_flag = 'Y' ORDER BY employee_id; 코드 설명..

• format_list_bulleted SQL
• · 2023. 10. 1.
• textsms

#104. [LeetCode / MySQL] 1731. The Number of Employees Which Report to Each Employee

문제 입력 코드 SELECT e2.employee_id, e2.name, COUNT(*) AS reports_count, ROUND(AVG(e1.age)) AS average_age FROM Employees AS e1 INNER JOIN Employees AS e2 ON e1.reports_to = e2.employee_id GROUP BY e2.employee_id, e2.name ORDER BY e2.employee_id 코드 설명 #SELECT #COUNT #ROUND #AVG #INNER JOIN #GROUP BY #ORDER BY 문제 출처 LeetCode - The World's Leading Online Programming Learning Platform Level up your codi..

• format_list_bulleted SQL
• · 2023. 9. 30.
• textsms

#103. [LeetCode / MySQL] 1045. Customers Who Bought All Products

문제 입력 코드 SELECT customer_id FROM Customer GROUP BY customer_id HAVING COUNT(DISTINCT(product_key)) = (SELECT COUNT(product_key) FROM Product); 코드 설명 #SELECT #GROUP BY #HAVING #COUNT #DISTINCT 문제 출처 LeetCode - The World's Leading Online Programming Learning Platform Level up your coding skills and quickly land a job. This is the best place to expand your knowledge and get prepared for your next i..

• format_list_bulleted SQL
• · 2023. 9. 29.
• textsms

#102. [LeetCode / MySQL] 619. Biggest Single Number

문제 입력 코드 SELECT MAX(num) as num FROM MyNumbers WHERE num NOT IN ( SELECT num FROM MyNumbers GROUP BY num HAVING COUNT(*) > 1) 코드 설명 #SELECT #MAX #NOT IN #GROUP BY #HAVING #COUNT 문제 출처 LeetCode - The World's Leading Online Programming Learning Platform Level up your coding skills and quickly land a job. This is the best place to expand your knowledge and get prepared for your next interview. leet..

• format_list_bulleted 카테고리 없음
• · 2023. 9. 28.
• textsms

#101. [LeetCode / MySQL] 1729. Find Followers Count

문제 입력 코드 SELECT user_id, COUNT(follower_id) AS followers_count FROM Followers GROUP BY user_id ORDER BY user_id ASC; 코드 설명 #SELECT #COUNT #GROUP BY #ORDER BY 문제 출처 LeetCode - The World's Leading Online Programming Learning Platform Level up your coding skills and quickly land a job. This is the best place to expand your knowledge and get prepared for your next interview. leetcode.com

• format_list_bulleted SQL
• · 2023. 9. 27.
• textsms