문제 입력 코드 1. MAX SELECT MAX(PRICE) AS MAX_PRICE FROM PRODUCT; 2. LIMIT SELECT PRICE AS "MAX_PRICE" FROM PRODUCT ORDER BY PRICE DESC LIMIT 1; → LIMIT=1를 사용하면 전체 레코드를 조회하고 1개만 보여주게 되므로 테이블의 크기가 커지면 성능 저하를 일으킬 수 있음 코드 설명 #SELECT #MAX #ORDER BY #LIMIT 문제 출처 https://school.programmers.co.kr/learn/courses/30/lessons/131697
문제 입력 코드 1. MAX SELECT MAX(DATETIME) AS '시간' FROM ANIMAL_INS; 2. LIMIT SELECT DATETIME AS "시간" FROM ANIMAL_INS ORDER BY DATETIME DESC LIMIT 1; 코드 설명 #SELECT #MAX #ORDER BY #LIMIT 문제 출처 https://school.programmers.co.kr/learn/courses/30/lessons/59415
문제 입력 코드 1. AND SELECT board.TITLE, board.BOARD_ID, reply.REPLY_ID, reply.WRITER_ID, reply.CONTENTS, DATE_FORMAT(reply.CREATED_DATE, '%Y-%m-%d') AS CREATED_DATE FROM USED_GOODS_BOARD as board JOIN USED_GOODS_REPLY AS reply ON board.BOARD_ID = reply.BOARD_ID WHERE (board.CREATED_DATE >= '2022-10-01') AND (board.CREATED_DATE